Simply Supported Beam with Uniform Load

The first beam everyone learns and the one that still covers most floor framing: a single span, simply supported, carrying a uniform load.

The equation

Mmax = wL2/8 at midspan
Vmax = R = wL/2 at each support
δmax = 5wL4/384EI at midspan
  • w is the load per unit length, in kN per meter
  • L is the span between supports, in meters
  • E is the modulus of elasticity of the material
  • I is the second moment of area of the section
  • δ is the vertical deflection
w = 10 kN/mL = 6 mBending moment, sagging plotted upMmax = wL2 /8 = 45 kNmcalculatgeek.com
The middle half of the parabola sits above three quarters of the peak: moment fades slowly away from midspan, which is why curtailing steel or reducing section too early catches people out.

Worked example

Take a 6 m span carrying 10 kN/m, with E = 200 GPa and I = 8.0 × 107 mm4, so EI = 16000 kNm2. Each reaction is 10 × 6/2 = 30 kN. The midspan moment is 10 × 62/8 = 45 kNm. Deflection is 5 × 10 × 64/(384 × 16000) = 0.0105 m, call it 10.5 mm, or span over 569. A span over 360 limit would allow 16.7 mm, so this section passes with a third in hand. The same case run through an independent numerical solve lands on the same numbers.

When to use it

Elastic behaviour, a prismatic section, small deflections, and shear deformation ignored, which is fine once the span passes about ten times the depth. Real seats are never perfectly frictionless pins, so measured deflections usually come in below the formula: treat it as a safe upper bound. Once there is more than one span or the load pattern moves, the continuous analyzer is the honest tool.

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