How to Find the Circumcenter of a Triangle

The short answer

where two perpendicular bisectors cross

Take two sides, find the line that cuts each in half at a right angle, and see where those two lines meet. That point is the same distance from all three corners.

The circumcenter is the centre of the one circle that passes through all three corners of a triangle. Unlike the centroid it cannot be averaged out of the coordinates, because it is defined by equal distances rather than by balance.

Why perpendicular bisectors

The perpendicular bisector of a segment is the set of every point equidistant from its two ends. That is not a fact about triangles, it is what a perpendicular bisector is.

So take the bisector of one side and every point on it is equally far from those two corners. Take the bisector of a second side and every point on that is equally far from its two corners. Where they cross, a single point is equidistant from all three, and a circle centred there passes through every one of them.

The third bisector is not needed. It has to pass through the same point, because that point already sits equidistant from the two corners the third side connects. Drawing it is a check, not a step.

1

Take two sides

Any two will do. Pick the ones with the friendliest coordinates.

2

Bisect each at a right angle

Find each midpoint, then the line through it perpendicular to that side.

3

Solve where they cross

That intersection is the circumcenter, equidistant from all three corners.

A worked example

Take a right triangle with corners at (0,0), (6,0) and (0,8). The side from (0,0) to (6,0) lies along the x axis, its midpoint is (3,0), and the line through that at a right angle is simply x = 3.

The side from (0,0) to (0,8) lies along the y axis, its midpoint is (0,4), and the perpendicular there is y = 4. The two cross at (3,4).

Check the distances. From (3,4) to (0,0) is the square root of 9 plus 16, which is 5. To (6,0) is the square root of 9 plus 16 again, also 5. To (0,8) is the square root of 9 plus 16 once more, still 5. All three match, so the circle centred at (3,4) with radius 5 passes through every corner.

A right triangle with legs of 6 and 8 inside a dashed circle, with perpendicular bisectors meeting at 3 comma 4 and three lines of length 5 drawn from that point to each corner.
On this triangle the circumcenter lands exactly on the middle of the hypotenuse. That is not a coincidence of these numbers, it happens on every right triangle.

Perpendicular bisectors, not angle bisectors

The two get confused constantly and they find different points. A perpendicular bisector cuts a side in half at a right angle and leads to the circumcenter. An angle bisector splits a corner in half and leads to the incenter, the centre of the inscribed circle.

perpendicular bisectorgivescuts a side in halfcircumcenter

equidistant from the three corners

angle bisectorgivescuts a corner in halfincenter

equidistant from the three sides, a different point entirely

Where it lands depends on the triangle

On an acute triangle the circumcenter sits inside. On a right triangle it lands exactly on the midpoint of the hypotenuse, which is why the hypotenuse is a diameter of the circumcircle. On an obtuse triangle it falls outside the shape altogether.

That last case surprises people, but nothing is wrong. The circle still passes through all three corners, and its centre simply happens to lie beyond one of the sides. If your answer lands outside, check whether the triangle is obtuse before assuming an error.

Mistakes that catch people out

  • Using angle bisectors instead. Those meet at the incenter, which is a different point.
  • Using medians instead. Those meet at the centroid, which is a third different point.
  • Assuming it must be inside. On an obtuse triangle the circumcenter falls outside, and that is correct.
  • Finding the midpoint and stopping. The midpoint is where the bisector starts. You still need the perpendicular line through it.
  • Taking the perpendicular slope wrongly. It is the negative reciprocal. A side of slope 2 needs a bisector of slope minus a half.

Practice questions

  1. Corners at (0,0), (8,0) and (0,6). Find the circumcenter.
  2. Corners at (0,0), (10,0) and (0,10). Find the circumcenter.
  3. Corners at (2,0), (8,0) and (5,4). Find the circumcenter.
  4. A right triangle has hypotenuse from (0,0) to (6,8). Where is the circumcenter?
  5. Corners at (0,0), (4,0) and (0,4). Find the circumradius.
Show the answers
  1. (4, 3), the midpoint of the hypotenuse, and 5 from every corner
  2. (5, 5), the midpoint of the hypotenuse, and 7.07 from every corner
  3. x = 5 by symmetry, and solving the distances gives (5, 0.875)
  4. the midpoint of the hypotenuse, which is (3, 4)
  5. the circumcenter is (2, 2) and the radius is 2.83

Common questions

How do I find the circumcenter of a triangle?

Find the perpendicular bisector of two sides and see where they cross. That point is the same distance from all three corners.

What is the circumcenter?

The centre of the one circle passing through all three corners. It is equidistant from every vertex, which is what defines it.

Do I need all three bisectors?

No. Two is enough, since the third always passes through the same point. Drawing it is a useful check rather than a requirement.

Can the circumcenter fall outside the triangle?

Yes. On an obtuse triangle it lands outside, and on a right triangle it sits exactly on the hypotenuse midpoint.

Is the circumcenter the same as the centroid?

No. The centroid is the balance point and always sits inside. The two coincide only on an equilateral triangle.

What is the difference between the circumcenter and the circumradius?

The circumcenter is a point, given as coordinates. The circumradius is a length, the distance from that point out to any corner.

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