How to Find the Area of a Trapezoid

The short answer

A = (a + b) / 2 × h

Add the two parallel sides, halve the total, then multiply by the perpendicular distance between them. Parallel sides of 12 and 20 with a height of 7 give a mean of 16, and 16 times 7 is an area of 112 square units. The height is the perpendicular gap, never the sloping side.

A trapezoid is a rectangle that changes width as it goes. Start at 12 across the top, finish at 20 across the bottom, and because the change is steady the average width is simply the mean of the two ends. Once you see it that way the formula stops being something to memorise: it is average width times height, which is what every area calculation has been since the rectangle.

The mean of the parallel sides is the whole idea

Draw a line across the middle of a trapezoid, joining the midpoints of the two sloping sides. That line is called the midline, and its length is exactly the mean of the two parallel sides. For 12 and 20 it measures 16, every time, whatever the sloping sides are doing. The trapezoid has the same area as a rectangle 16 wide and 7 tall, because the triangle of material sticking out below the midline is exactly the triangle missing above it.

That is also why the formula does not care whether the shape leans. A right trapezoid with one vertical side and a symmetric one with two equal slopes have the same area as long as a, b and h match. The lean moves material sideways without adding any, the same way it does in a parallelogram.

1

Add

The two parallel sides only. 12 plus 20 is 32. The sloping sides play no part in this.

2

Halve

32 over 2 is 16, which is the average width, and also the length of the midline.

3

Multiply

16 times the perpendicular height of 7 gives 112 square units.

Why halving the sum works

Take a second copy of the trapezoid, turn it through half a turn and slide it against the first. The two interlock perfectly, because the sloping side of one matches the sloping side of the other. What you get is a parallelogram, and its base is a plus b.

A trapezoid with parallel sides of 12 and 20 and a height of 7, its midline of 16 drawn across, shown beside two copies of the same trapezoid turned to interlock into a parallelogram 32 wide and 7 tall, with the arithmetic reaching an area of 112.
This is the same trick that gives a triangle its half. Two copies make a shape you already know how to measure, so one copy is half of it, and the division by two in the formula is that step written down.

The parallelogram is 32 wide and 7 tall, so it holds 224 square units. It is built from two identical trapezoids, so one of them holds 112. Divide a plus b by two and you have done exactly that, just in a different order.

The formula also quietly contains two shapes you already know. Set a equal to b and the mean is just that side, so it becomes a parallelogram at b times h. Shrink a to zero and the mean is half of b, so it becomes a triangle at b h over 2. One formula, three shapes, which is a fair reason to learn this one properly rather than the other two separately.

A worked check you can repeat on paper

Parallel side a, the shorter one12
Parallel side b, the longer one20
Perpendicular height h7
Sum of the parallel sides12 + 20 = 32
Mean of them, which is the midline16
Mean times height16 × 7 = 112
Check one, split along a diagonal12×7/2 + 20×7/2 = 42 + 70
Check one result112
Check two, a rectangle plus a triangle12×7 + 8×7/2 = 84 + 28
Check two result112
Check three, shoelace on the corners(0,0) (20,0) (16,7) (4,7)
Check three result112

Four routes, one number. The shoelace check is worth running once for yourself, because it uses nothing but the corner coordinates and so it does not borrow the height, the midline or the formula. If your own trapezoid disagrees between these routes, the measurement is wrong rather than the arithmetic.

When all you have is the four sides

This is the case that sends people hunting, and the honest answer is that it is recoverable but awkward. Call the parallel sides a and b, and the two sloping sides c and d. Slide one sloping side across until both meet, and you have a triangle whose sides are b minus a, c and d. Run Heron on that triangle, and its height is the height of the trapezoid.

Written out, with k standing for b minus a and s for half of k plus c plus d, the height is 2 over k, times the square root of s(s − k)(s − c)(s − d). For the trapezoid above, with sloping sides of 8.0623 each, that returns a height of exactly 7. It also works on the right angled version, where the sides are 7 and 10.6301, and returns 7 again.

Measure the height

h = 7, area 112

One measurement, no ambiguity, and an error in it moves the answer in proportion. This is the route to take whenever the shape is in front of you.

Recover it from four sides

h = 2/k × √(s(s−k)(s−c)(s−d))

Correct, but it divides by b minus a, so it fails outright on a parallelogram and gets jumpy when the parallel sides are nearly equal.

That division is the thing to watch. As a approaches b the divisor shrinks toward zero, so a small error in a measured side gets multiplied into a large error in the height. At a equals b it breaks completely, which is not a flaw in the algebra: a parallelogram of given side lengths can lean to any angle, so its area genuinely is not determined by its sides. Four side lengths alone do not fix a four sided shape.

Mistakes that catch people out

  • Using a sloping side as the height. The most common error by a distance. The slope is always longer than the perpendicular gap, so the area always comes out too big. In the worked example the slope is 8.06 against a true height of 7, which inflates the answer by 15 percent.
  • Adding all four sides before halving. Only the two parallel sides go into the sum. The sloping sides never appear in the formula at all, which is exactly why two trapezoids that look nothing alike can have identical areas.
  • Averaging the wrong pair. In a trapezoid drawn on its side, the parallel pair is the left and right, not the top and bottom. Identify which pair is parallel before reaching for a and b.
  • Forgetting that the height is measured between the parallel sides. Not from a corner, not along an edge, and not the longest distance across the shape. Perpendicular, from one parallel side to the other.
  • Mixing units. Sides in centimetres with a height in metres produces a number that means nothing. Convert first, and remember area scales with the square, so a factor of 100 in length becomes 10,000 in area.

Try these

  1. Parallel sides 6 and 10, height 4. Find the area.
  2. Parallel sides 9 and 15, height 8. Find the area.
  3. Parallel sides 5 and 5, height 6. What shape is this, and does the formula still hold?
  4. A trapezoid has an area of 90 and parallel sides of 7 and 11. Find its height.
  5. An isosceles trapezoid has parallel sides of 10 and 18 and sloping sides of 5. Find the height, then the area.
Show the answers
  1. Mean is 8, and 8 times 4 is 32 square units.
  2. Mean is 12, and 12 times 8 is 96 square units.
  3. A parallelogram, and yes. The mean of 5 and 5 is 5, and 5 times 6 is 30, which is the same as base times height. The trapezoid formula contains this case.
  4. Rearrange to h = 2A / (a + b). That is 180 over 18, so the height is 10.
  5. The overhang on each end is (18 − 10) / 2 = 4, so the height is √(25 − 16) = 3. The mean is 14, and 14 times 3 is 42 square units.

Common questions

What is the formula for the area of a trapezoid?

Add the two parallel sides, halve the total and multiply by the perpendicular height. In symbols, A = (a + b) h / 2. Sides of 12 and 20 with a height of 7 give 112 square units.

How do you find the area of a trapezoid without the height?

Recover the height from the four side lengths first, using Heron on the triangle whose sides are b minus a, c and d. It works, but it divides by b minus a, so it fails when the parallel sides are equal and becomes unreliable when they are close. If you can measure the height directly, do that instead.

Is the height the same as the sloping side?

No, and confusing the two is the most common way this calculation goes wrong. The height is the perpendicular distance between the parallel sides. The sloping side is longer, and using it in place of the height always overstates the area.

What is the midline of a trapezoid?

The segment joining the midpoints of the two sloping sides. Its length is always the mean of the parallel sides, so for sides of 12 and 20 the midline is 16. The area is simply the midline times the height.

What is the difference between a trapezoid and a trapezium?

Naming, not geometry. In North America a trapezoid has one pair of parallel sides. In British usage that shape is a trapezium, and the word trapezoid means a quadrilateral with no parallel sides at all. The formula on this page applies to the shape with one parallel pair, whichever name your textbook uses.

How do you find the height from the area?

Rearrange to h = 2A / (a + b). An area of 90 with parallel sides of 7 and 11 gives a height of 180 over 18, which is 10.

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